In the diagram above, BD = 8, AB = 6 and ED=5? What is the length of AE? (Note: figure not drawn to scale.)
A. 3
B. 4
C. 5
D. 7
E. 10
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2 comments:
The problem is actually simpler than the figure suggests because the angles at points C and F are actually irrelevant. The only thing that matters is that at point B we have a right-angle (90 degrees). Thus, by Pitagoras theorem we have AB^2 + BD^2 = AD^2. With AB=6 and BD=8, the sum of these two quantities squared is 100. Thus the total length of the hypotenuse AD must be 10. As AD is AE plus ED, which know to have length 5, the remaining length AE must be 5. The correct option should be C.
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