Sarah receives 10z coins in addition to what she already has. She then has 5y+1 times as many coins as she had originally. In terms of y and z, how many coins did Sarah have originally?
A. 10z(5y + 1)
B. (5y + 1)/10z
C. 2z/y
D. 10/(5y + 1)
E. 10 / (5y + 10)
source: www.800score.com
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Let x be the original number of coins Sarah had. Adding 10z to that ammount we get a number (5y+1) times x. Thus we may solve our equation in order to x:
10z + x = (5y+1)x or
10z = (5y + 1)x - x = (5y +1-1)x
Then x = 10z/5y = 2z/y.
We take option C.
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